GeminiHeat wrote:
How much more interest will maria receive if she invests 1000$ for one year at x % annual interest, compounded semianually, than if she invest 1000$ for one year at x percent annual interest, compounded annually?
A. 5x
B. 10x
C. \(\frac{x^2}{20}\)
D. \(\frac{x^2}{40}\)
E. \((10x+\frac{x^2}{40})\)
Its quicker if we assume some value of x
Let x = 10
C.I (Compounded semi-annually) = \(1000(1 + \frac{10}{200})^2 = 1000(1.05)^2 = $1102.5\)
C.I (Compounded annually) = \(1000(1 + \frac{10}{100})^1 = 1000(1.1)^1 = $1100\)
How much more?
$2.5 more
Now, put the value of x as 10 and see which option is giving us 2.5?
A. 5x
5(10) = 50B. 10x
10(10) = 100C. \(\frac{x^2}{20}\)
\(\frac{10^2}{20} = 5\)D. \(\frac{x^2}{40}\)
\(\frac{10^2}{40} = 2.5\)E. \((10x+\frac{x^2}{40})\)
\((10(10)+\frac{10^2}{40}) = 102.5\)Hence, option D