Carcass wrote:
If 82x+3=23x+6, then x =
(A) -3
(B) -1
(C) 0
(D) 1
(E) 3
To solve this question, we must first rewrite one or more of the expressions so they have the same baseWe can do this by replacing
8 with
23 to get:
(23)2x+3=23x+6Now apply the power of a power law to the left side to get:
26x+9=23x+6Now that we have the same bases, we know the exponents must be equal:
6x+9=3x+6Subtract
3x from both sides of the equation:
3x+9=6Subtract
9 from both sides of the equation:
3x=−3Divide both sides by
3 to get:
x=−1Answer: B