Carcass wrote:
Each of the 576 houses in Tenantville is owned by one of the following landlords: Matt, Gavin, Angela, or Susan. Matt and Angela together own twice as many houses as Gavin and Susan own. If Gavin owns 100 more houses than Susan owns, and Matt owns 100 more houses than Angela owns, how many houses does Susan own?
A) 46
B) 142
C) 146
D) 192
E) 242
Since we're trying to determine the number of houses Susan owns, let's focus on her info first.
Gavin owns 100 more houses than Susan ownsLet
x = number of houses Susan owns
So,
x+100 = number of houses Gavin owns
Matt and Angela together own twice as many houses as Gavin and Susan ownSo, combined houses of Matt and Angela = 2(combined houses of Gavin and Susan)
We get: combined houses of Matt and Angela = 2(
x +
x+100)
Simplify: combined houses of Matt and Angela = 2(2x + 100)
Simplify: combined houses of Matt and Angela =
4x + 200Each of the 576 houses in Tenantville is owned by one of the following landlords: Matt, Gavin, Angela, or SusanSo, (# of Matt's houses) + (# of Angela's houses) + (# of Gavin's houses) + (# of Susan's houses) = 576
We can combine the first two values to get: (combined houses of Matt and Angela) + (# of Gavin's houses) + (# of Susan's houses) = 576
Substitute to get:
4x + 200 +
x+100 +
x = 576
Simplify: 6x + 300 = 576
Solve to get: x = 46
Answer:
Cheers,
Brent
06 Jun 2017, 06:36 
76% (03:00) correct
