GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
f(x) = |x 2| + |2.5 x| + |3.6 x|
[#permalink]
24 Sep 2021, 10:34
24 Sep 2021, 10:34
1
8
Bookmarks
00:00
Question Stats:
52% (01:50) correct
47% (01:10) wrong based on 71 sessions
Hide Show timer Statistics
\(f(x) = |x – 2| + |2.5 – x| + |3.6 – x|\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
Minimum value of \(f(x)\) |
2.5 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
Re: f(x) = |x 2| + |2.5 x| + |3.6 x|
[#permalink]
24 Sep 2021, 14:27
24 Sep 2021, 14:27
1
1
Bookmarks
the absolute is minimized when its value is 0
setting up pair-wise function as below
\(min f(x)=|x–2|, x=2\)
\(min f(x)=|2.5-x|, x=2.5\)
\(min f(x)=|3.6-x|, x=3.6\)
we can notice that x is different, and we must choose one value for \(x\), because it's one and not pair-wise function
let us choose the middle value, \(x=2.5\), \(f(2.5)=|2.5–2|+|2.5–2.5|+|3.6–2.5|=1.6\)
answer is B, as Quantity A=1.6 < Quantity B=2.5
setting up pair-wise function as below
\(min f(x)=|x–2|, x=2\)
\(min f(x)=|2.5-x|, x=2.5\)
\(min f(x)=|3.6-x|, x=3.6\)
we can notice that x is different, and we must choose one value for \(x\), because it's one and not pair-wise function
let us choose the middle value, \(x=2.5\), \(f(2.5)=|2.5–2|+|2.5–2.5|+|3.6–2.5|=1.6\)
answer is B, as Quantity A=1.6 < Quantity B=2.5
KarunMendiratta wrote:
\(f(x) = |x – 2| + |2.5 – x| + |3.6 – x|\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
Minimum value of \(f(x)\) |
2.5 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
