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M is the sum of three consecutive odd integers, the least o
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07 Jun 2017, 02:02
07 Jun 2017, 02:02
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67% (01:55) correct
32% (01:36) wrong based on 107 sessions
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M is the sum of three consecutive odd integers, the least of which is \(t\). In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?
A) \(M + 12\)
B) \(M + 6\)
C) \(M - 6\)
D) \(M - 12\)
E) \(\frac{M}{2}\)
Re: M is the sum of three consecutive odd integers, the least o
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20 Sep 2017, 05:55
20 Sep 2017, 05:55
1
The sum of three consecutive integers, the least being t is M = t + (t+2) + (t+3) = 3t +6. The sum of three consecutive odd integers, the largest being t is (t-4) + (t-2) + t = 3t - 6. To get the answer in terms of M, we can substitute for 3t that from the first equation is equal to M-6 obtaining that the sum becomes M-6-6 = M-12. Thus answer D!
Re: M is the sum of three consecutive odd integers, the least o
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12 May 2018, 01:55
12 May 2018, 01:55
IlCreatore wrote:
The sum of three consecutive integers, the least being t is M = t + (t+2) + (t+3) = 3t +6. The sum of three consecutive odd integers, the largest being t is (t-4) + (t-2) + t = 3t - 6. To get the answer in terms of M, we can substitute for 3t that from the first equation is equal to M-6 obtaining that the sum becomes M-6-6 = M-12. Thus answer D!
If possible can you please explain your solution in a bit simpler way. will be thankful.
