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Carcass
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b < 0 [#permalink] New post   31 May 2022, 01:30
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\(b < 0\)


Quantity A
Quantity B
\([-2b]^2\)
\(-2b^2\)


A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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A
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GreenlightTestPrep
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Re: b < 0 [#permalink] New post   31 May 2022, 06:54
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Carcass wrote:
\(b < 0\)

Quantity A
Quantity B
\([-2b]^2\)
\(-2b^2\)


A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given


QUANTITY A: (-2b)² = (-2b)(-2b) = 4b²
QUANTITY B : -2b²

Since we know that b² must be positive, we can safely divide both quantities by b² to get:
QUANTITY A: 4
QUANTITY B : -2

Answer: A
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alsafaj
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Re: b < 0 [#permalink] New post   03 Jun 2022, 00:26
1
Quantity A is always positive, while quantity B is always negative.

The answer is (A)
Prep Club for GRE Bot
gmatclubot
Re: b < 0 [#permalink]
03 Jun 2022, 00:26
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