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Let d = number of dimes. Let p = number of pennies.

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Let d = number of dimes. Let p = number of pennies. [#permalink] New post   03 Jun 2022, 01:00
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Let d = number of dimes.
Let p = number of pennies.

Quantity A
Quantity B
0.10d + 0.01p
10d + p


A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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B
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BoomBoom
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Re: Let d = number of dimes. Let p = number of pennies. [#permalink] New post   03 Jun 2022, 02:02
1
5second approach.
Minimum value of d = 1
Minimum value of p = 1

Thus Quantity B will always be larger than A.
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Re: Let d = number of dimes. Let p = number of pennies. [#permalink] New post   03 Jun 2022, 13:41
The question doesn't state that the number of dimes and/or number of pennies are greater than 0. So how is it B?
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Re: Let d = number of dimes. Let p = number of pennies. [#permalink] New post   03 Jun 2022, 17:55
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rishivala wrote:
The question doesn't state that the number of dimes and/or number of pennies are greater than 0. So how is it B?


IF the question states

Let d = number of dimes.

d MUST be positive at least 1. Also the quantities are positive

Does not have much sense to say the dimes are zero. the quantities would be zero and the answer would be C

But the question would be meaningless

Quote:
Since the variables d and p refer to the number of dimes and pennies respectively, they must be positive whole numbers (it’s impossible to have −3 dimes, or 1/4 of a penny). Regardless of what numbers the variables represent, 1/10 of any positive number plus 1/100 of another positive number will always be less than the sum of the two whole numbers. Column B will always be greater
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gmatclubot
Re: Let d = number of dimes. Let p = number of pennies. [#permalink]
03 Jun 2022, 17:55
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