Carcass wrote:
If \(x - y = 2\) and \(x^2 - y^2\) = 16, then \(x^3 - y^3\) = ?
A. 97
B. 98
C. 99
D. 100
E. 152
Take: x² - y² = 16
Factor: (x + y)(x - y) = 16
Substitute to get: (x + y)(
2) = 16
Divide both sides of the equation by 2 to get:
x + y = 8We now have the following system of equations:
x - y = 2x + y = 8Add the two equations to get:
2x = 10, which means
x = 5Once we know
x = 5, we can plug this value into one of the two equations to learn that
y = 3Now that we know the values of x and y, x³ - y³ =
5³ -
3³ = 125 - 27 = 98
Answer: B