GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the figure, AD and BC are lines intersecting at O. What i
[#permalink]
22 Sep 2018, 09:21
22 Sep 2018, 09:21
1
Expert Reply
00:00
Question Stats:
91% (01:46) correct
8% (01:40) wrong based on 37 sessions
Hide Show timer Statistics
Attachment:
#GREpracticequestion In the figure, AD and BC are lines intersecting at O.jpg [ 20.85 KiB | Viewed 4829 times ]
In the figure, AD and BC are lines intersecting at O. What is the value of a ?
(A) 15
(B) 30
(C) 45
(D) 60
(E) 135
Re: In the figure, AD and BC are lines intersecting at O. What i
[#permalink]
01 Jul 2020, 22:50
01 Jul 2020, 22:50
1
To solve this problem, we should work with opposite angles which values are the same.
This means that:
5y/2=5x+5a
Reducing
y/2=x+a
a=y/2-x............................(1)
Also
y=2x+30
Reducing this expression, we obtain
y/2=x+15 .........................(2)
Replacing (2) in (1)
a=(x+15)-x
a=15
Answer=A
This means that:
5y/2=5x+5a
Reducing
y/2=x+a
a=y/2-x............................(1)
Also
y=2x+30
Reducing this expression, we obtain
y/2=x+15 .........................(2)
Replacing (2) in (1)
a=(x+15)-x
a=15
Answer=A
Attachments
Triangle.png [ 15.85 KiB | Viewed 2714 times ]
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: In the figure, AD and BC are lines intersecting at O. What i
[#permalink]
13 Feb 2021, 01:34
13 Feb 2021, 01:34
1
Carcass wrote:
Attachment:
#GREpracticequestion In the figure, AD and BC are lines intersecting at O.jpg
In the figure, AD and BC are lines intersecting at O. What is the value of a ?
(A) 15
(B) 30
(C) 45
(D) 60
(E) 135
Vertically opposite angles are equal
So, \(y = 2x + 30\)
and, \(5x + 5a\) = \(\frac{5(2x +30)}{2}\)
\(10x + 10a\) =\(10x + 150\)
\(10a = 150\)
\(a = 15\)
Hence, option A
