Carcass wrote:
If \(x = 9a^2\) and \(a < 0\), then \(\sqrt{x} =\)
(A) −3a
(B) 3a
(C) 9a
(D) 3a^2
(E) 81a
To avoid any silly mistakes, let's test a possible a-value.
For example, since we are told a is negative, it could be the case that
\(a = -2\), which means our equation becomes \(x = 9(-2)^2 = 36\)
If \(x = 36\), then \(\sqrt{x} =\sqrt{36}\)
\(= 6\)This means the correct answer will evaluate to
6 when
a = -2So, we'll plug \(a = -2\) into the five answer choices to get:
(A) −3a = -3(
-2) =
6. PERFECT!
(B) 3a = 3(
-2) =
-6. No good. Eliminate.
(C) 9a = 9(
-2) =
-18. No good. Eliminate.
(D) 3a^2 = 3(
-2)^2 =
12. No good. Eliminate.
(E) 81a = 81(
-2) =
-162. No good. Eliminate.
Answer: A