Carcass wrote:
If x=9a2 and a<0, then √x=
(A) −3a
(B) 3a
(C) 9a
(D) 3a^2
(E) 81a
To avoid any silly mistakes, let's test a possible a-value.
For example, since we are told a is negative, it could be the case that
a=−2, which means our equation becomes
x=9(−2)2=36If
x=36, then
√x=√36 =6This means the correct answer will evaluate to
6 when
a = -2So, we'll plug
a=−2 into the five answer choices to get:
(A) −3a = -3(
-2) =
6. PERFECT!
(B) 3a = 3(
-2) =
-6. No good. Eliminate.
(C) 9a = 9(
-2) =
-18. No good. Eliminate.
(D) 3a^2 = 3(
-2)^2 =
12. No good. Eliminate.
(E) 81a = 81(
-2) =
-162. No good. Eliminate.
Answer: A