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Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
At a certain restaurant, a meal consists of 2 different meats chosen
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09 Jun 2022, 09:41
09 Jun 2022, 09:41
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At a certain restaurant, a meal consists of 2 different meats chosen from pork, fish, chicken and beef, and 1 dessert chosen from cake, pie and ice cream.
If two brothers randomly choose the items of their meals, what is the probability they order the same meal?
(A) 1/48
(B) 1/36
(C) 1/24
(D) 1/18
(E) 1/12
If two brothers randomly choose the items of their meals, what is the probability they order the same meal?
(A) 1/48
(B) 1/36
(C) 1/24
(D) 1/18
(E) 1/12
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: At a certain restaurant, a meal consists of 2 different meats chosen
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13 Jun 2022, 07:23
13 Jun 2022, 07:23
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GreenlightTestPrep wrote:
At a certain restaurant, a meal consists of 2 different meats chosen from pork, fish, chicken and beef, and 1 dessert chosen from cake, pie and ice cream.
If two brothers randomly choose the items of their meals, what is the probability they order the same meal?
(A) 1/48
(B) 1/36
(C) 1/24
(D) 1/18
(E) 1/12
If two brothers randomly choose the items of their meals, what is the probability they order the same meal?
(A) 1/48
(B) 1/36
(C) 1/24
(D) 1/18
(E) 1/12
Let's first calculate the total number of possible meals one can order at the restaurant.
The number of ways to choose 2 different meats from 4 options = 4C2 = (4)(3)/(2)(1) = 6
The number of ways to choose 1 dessert from 3 options = 3
So, the TOTAL number of possible meals the first brother can choose from = (6)(3) = 18
Once the first brother has chosen his meal, there's only 1 way (out of 18 options) the second brother's selection can match the first brother's selection.
So, P(both brothers order the same meal) = 1/18
Answer: D
gmatclubot
Re: At a certain restaurant, a meal consists of 2 different meats chosen [#permalink]
13 Jun 2022, 07:23
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