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Carcass
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1/19 - 1 [#permalink] New post   06 Sep 2018, 16:12
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Quantity A
Quantity B
\(\frac{1}{19} - 1\)
\(\frac{1}{18} - 1\)


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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B
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GreenlightTestPrep
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Re: 1/19 - 1 [#permalink] New post   07 Sep 2018, 05:35
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Carcass wrote:
Quantity A
Quantity B
\(\frac{1}{19} - 1\)
\(\frac{1}{18} - 1\)


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

Kudos for the right answer and solution.


We can solve this question using matching operations

Given:
Quantity A: 1/19 - 1
Quantity B: 1/18 - 1

Add 1 to both quantities:
Quantity A: 1/19
Quantity B: 1/18

At this point, we might recognize that 1/18 is greater than 1/19.
Answer: B

However, we can also continue using matching operations

Multiply both quantities by 19 to get:
Quantity A: 1
Quantity B: 19/18

Quantity B is still bigger!

Multiply both quantities by 18 to get:
Quantity A: 18
Quantity B: 19


Yep, Quantity B is must be bigger


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Re: 1/19 - 1 [#permalink] New post   19 Jun 2022, 10:49
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: 1/19 - 1 [#permalink]
19 Jun 2022, 10:49
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