Note: \(\frac{a + b + c + d + e + f + g + h + i + j + k}{11}\) is the AVERAGE of the values from a to k


There are many possible scenarios that satisfy the given information:

case a: The values for k, j, i, h, g, f, e, d, c, b, a are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1,000,000,000,000,000,000 respectively.
So, we have:
Quantity A: e = 7
Quantity B: The average is much bigger than greater than 7
So, Quantity B is greater

case b: The values for k, j, i, h, g, f, e, d, c, b, a are -1,000,000,000,000,000,000, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, respectively.
So, we have:
Quantity A: e = 6
Quantity B: The average is much smaller than greater than 6
So, Quantity A is greater

Answer: D