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Re: A man leaves a place at 11 a.m. traveling at a rate of 40 miles per ho [#permalink]
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However, this question seems complicated, but it is easy -- It is suppose to consume your time; that's all!

First find the distance traveled by A in 2 hours (11Am to 1Pm), which is almost 40*2 = 80 miles
Which means that Person A is 80 miles ahead when Person 2 starts.
So, here is manual and simple solution:
Person A distance with respect to Hours: [80 - 120 - 160 - 200 - 240]
Person B distance with respect to Hours: [0 - 60 - 120 - 180 - 240]
Time: ------------------------------------> [0Hrs - 1hrs- 2hrs- 3hr- 4hr]
Means after 4hr they will meet, and that time is 5Pm
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Re: A man leaves a place at 11 a.m. traveling at a rate of 40 miles per ho [#permalink]
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Re: A man leaves a place at 11 a.m. traveling at a rate of 40 miles per ho [#permalink]
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