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x>0 and 2x/3<7
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07 Jun 2017, 00:52
07 Jun 2017, 00:52
Expert Reply
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Question Stats:
68% (00:41) correct
31% (00:45) wrong based on 187 sessions
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\(x >0\) and \(\frac{2x}{3} < 7\)
Quantity A |
Quantity B |
\(x^2\) |
\(100\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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x>0 and 2x/3<7
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14 Jun 2017, 06:25
14 Jun 2017, 06:25
1
Carcass wrote:
\(x>0\) and \(\frac{2x}{3}<7\)
Quantity A |
Quantity B |
x^2 |
100 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Take: 2x/3 < 7
Multiply both sides by 3 to get: 2x < 21
Divide both sides by 2 to get: x < 10.5
We're also told that x > 0, which is the same as 0 < x
We can COMBINE the inequalities to get: 0 < x < 10.5
In other words, x is BETWEEN 0 and 10.5
We're comparing x² and 100
Let's PLUG IN some values for x
x = 1
We get:
Quantity A: 1² = 1
Quantity B: 100
Quantity B is greater
x = 10
We get:
Quantity A: 10² = 100
Quantity B: 100
The quantities are equal
Answer: D
Re: x>0 and 2x/3<7
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11 Feb 2019, 20:26
11 Feb 2019, 20:26
2x/3 < 7
Solving further 2x < 21, hence x < 10.5
So 10.5<x>0
So we cant really determine the value of x
Answer is D
Solving further 2x < 21, hence x < 10.5
So 10.5<x>0
So we cant really determine the value of x
Answer is D
