Re: A small company employs 3 men and 5 women. If a team of 4 employees is
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09 Jul 2022, 01:19
Total amount of possible choices is
8! / 4! 4! = 8 x 6 x 7 x 5 / 4 x 3 x 2 = 70
the only way to have exactly 2 women is to have 2 men so the number of ways we can select 2men from 4 is
3!/ 2! = 3
the number of ways we can select 2 women from 5 is
5! /2! 3! = 5 x 4 / 2 = 10
the total different ways you can have 2 women and 2 men
3 x 10 = 30
desired outcome / total outcomes = probability -> 30 / 70 = 3/7