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In the figure, P and Q are centers of the two circles of rad
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24 Mar 2019, 00:27
24 Mar 2019, 00:27
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Question Stats:
38% (01:22) correct
61% (01:31) wrong based on 88 sessions
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#GREpracticequestion In the figure, P and Q are centers .jpg [ 28.93 KiB | Viewed 8696 times ]
In the figure, P and Q are centers of the two circles of radii 3 and 4, respectively. A and B are the points at which a common tangent touches each circle.
Quantity A |
Quantity B |
\(AB\) |
\(PQ\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Re: In the figure, P and Q are centers of the two circles of rad
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27 Mar 2019, 14:16
27 Mar 2019, 14:16
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Tough one
shot7.jpg [ 32.12 KiB | Viewed 8270 times ]
\(ABPD\) is a rectangle and \(AB=DP\). A is \(\angle90°\) so also the corresponding angle D must be \(90°\). If D is \(90° PQ\) is the longest side of the \(\trinagle PDQ\).
Sp \(PQ\) is > of side \(DP\). \(DP\) is \(= AB\).
Therefore, \(PQ > AB\)
B is the answer
Attachment:
shot7.jpg [ 32.12 KiB | Viewed 8270 times ]
\(ABPD\) is a rectangle and \(AB=DP\). A is \(\angle90°\) so also the corresponding angle D must be \(90°\). If D is \(90° PQ\) is the longest side of the \(\trinagle PDQ\).
Sp \(PQ\) is > of side \(DP\). \(DP\) is \(= AB\).
Therefore, \(PQ > AB\)
B is the answer
General Discussion
Re: In the figure, P and Q are centers of the two circles of rad
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27 Mar 2019, 08:57
27 Mar 2019, 08:57
1
please provide explanation for the answer?
