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60% of the marbles in a jar are red. Twenty marbles....
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Updated on: 03 May 2020, 08:45
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60 percent of the marbles in a jar are red. Twenty marbles are to be added to the jar, three of which will be red. If 50 percent of its marbles, after the addition, are to be red, how many marbles will be in the jar?
Suppose that the marble are 100 and the red are 60% . After the marble are 63 and they are the 50% that means the middle of the average is less than before.
The upper extreme is 100 but now our average is LESS so cannot be 100 but 90.
100 was when the red were 60% but now are 50% Logically the overall marble cannot be 100
Re: 60% of the marbles in a jar are red. Twenty marbles....
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19 Jul 2022, 12:44
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Here's another method. If initial 60 percent is converted to 50 percent upon adding 15 percent of red, then the fraction of 15 percent red collection is 2/9. Now 15 percent of 2/9 of total is 3. i.e 3/20 * 2/9 * x = 3 So x = 90
Re: 60% of the marbles in a jar are red. Twenty marbles....
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22 Jul 2022, 12:03
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Initial number of marbles = Y
Initial number of red marbles =60/100Y = 3/5Y Number of non red marbles = 40/100y = 2/5Y
If 20 marbles added and 3 goes to red = 3/5Y + 3
Non red = 2/5Y + 17 If new red marbles in jar is 50% let new number of marbles be X So X/2 =3/5Y + 3 Non red will be X/2 = 2/5Y + 17 Simultaneous equation becomes 5X - 4Y = 170 5X - 6Y = 30 Y = 70 substituting for Y gives new number of red and non red marbles to be 45 Answer = 90.
Re: 60% of the marbles in a jar are red. Twenty marbles....
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18 Sep 2023, 05:42
Hello from the GRE Prep Club BumpBot!
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