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The average of ten numbers is 11. The average of six of these numbers
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17 Jul 2022, 23:39
17 Jul 2022, 23:39
Expert Reply
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Question Stats:
72% (01:08) correct
27% (00:43) wrong based on 18 sessions
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The average of ten numbers is 11. The average of six of these numbers is 13. The average of the remaining numbers is x.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
40 |
4x |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas for a Q170
GRE - Math Book
Re: The average of ten numbers is 11. The average of six of these numbers
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25 Jul 2022, 03:28
25 Jul 2022, 03:28
Expert Reply
Re: The average of ten numbers is 11. The average of six of these numbers
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25 Jul 2022, 20:04
25 Jul 2022, 20:04
1
Carcass wrote:
The average of ten numbers is 11. The average of six of these numbers is 13. The average of the remaining numbers is x.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
40 |
4x |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas for a Q170
GRE - Math Book
If the average of ten numbers is 11, then
\(total/10 = 11\)
therefore, the total sum of those numbers is \(110\).
Using the same principle, the total sum of the six numbers is \(total_{2} = 6*13 = 78\). Due to this, the total sum of the remaining numbers is \(110-78 = 32\), and its average is \(32/4 = 8 = x\).
Finally, replacing,
Quantity A = 40
Quantity B = 8*4 = 32
Quantity A > Quantity B
