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Joined: 20 Feb 2017
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The average of six consecutive integers in increasing order
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07 Nov 2019, 22:38
07 Nov 2019, 22:38
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Expert Reply
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Question Stats:
78% (01:44) correct
21% (00:09) wrong based on 14 sessions
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The average of six consecutive integers in increasing order of size is \(9\frac{1}{2}\). What is the average of the last three integers?
(A) 8
(B) \(9\frac{1}{2}\)
(C) 10
(D) 11
(E) 19
(A) 8
(B) \(9\frac{1}{2}\)
(C) 10
(D) 11
(E) 19
Re: The average of six consecutive integers in increasing order
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08 Nov 2019, 04:07
08 Nov 2019, 04:07
1
Expert Reply
The avreage is 9.5
since the integers are consecutive they could be also all equal and at most 6
3*6=18 and the average is 9.5
D must be the answer without further calculation
since the integers are consecutive they could be also all equal and at most 6
3*6=18 and the average is 9.5
D must be the answer without further calculation
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The average of six consecutive integers in increasing order
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04 Aug 2022, 23:45
04 Aug 2022, 23:45
1
Theory
The average of six consecutive integers in increasing order of size is \(9\frac{1}{2}\)
Since there are 6 numbers so Mean = Median = Mean of middle two consecutive integers = \(9\frac{1}{2}\) = 9.5
=> the two middle integers are 9 and 10
So, six numbers are 7, 8, 9, 10, 11, 12
The average of the last three integers
Last three integers are 10 ,11, 12
Since, there are 3 consecutive integers so Mean = Median = Middle term = \(2^{nd}\) term = 11
So, Answer will be D.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
- ➡ In case of consecutive integers Mean = Median
➡ In case of even number of numbers in the set: Median is the mean of the two middle numbers (after the numbers are arranged in the increasing / decreasing order)
➡ In case of odd number of numbers in the set: Median is the middle number (after the numbers are arranged in increasing/ decreasing order )
The average of six consecutive integers in increasing order of size is \(9\frac{1}{2}\)
Since there are 6 numbers so Mean = Median = Mean of middle two consecutive integers = \(9\frac{1}{2}\) = 9.5
=> the two middle integers are 9 and 10
So, six numbers are 7, 8, 9, 10, 11, 12
The average of the last three integers
Last three integers are 10 ,11, 12
Since, there are 3 consecutive integers so Mean = Median = Middle term = \(2^{nd}\) term = 11
So, Answer will be D.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
