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n=(1/n)^n for all integers n > 0

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n=(1/n)^n for all integers n > 0 [#permalink] New post   19 Jul 2019, 09:17
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\(\boxed {n}\)\(=(\frac{1}{n})^n\) for all integers n > 0. What is the value of \(\boxed {3}\) ?

A. \(\frac{1}{27}\)

B. \(\frac{1}{3}\)

C. \(1\)

D. \(3\)

E. \(27\)
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Re: n=(1/n)^n for all integers n > 0 [#permalink] New post   14 Apr 2020, 09:23
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\(\boxed {3}\) = (1/3)^3
= 1/27
Hence, A is the Answer
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Re: n=(1/n)^n for all integers n > 0 [#permalink] New post   08 Aug 2022, 00:00
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Given that \(\boxed {n}\)\(=(\frac{1}{n})^n\) and we need to find the value of \(\boxed {3}\)

To find \(\boxed {3}\) we need to compare what is inside the square in \(\boxed {3}\) and \(\boxed {n}\)

=> We need to substitute n with 3 in \(\boxed {n}\)\(=(\frac{1}{n})^n\) to get the value of \(\boxed {3}\)

=> \(\boxed {3}\)\(=(\frac{1}{3})^3\) = \(\frac{1}{27}\)

So, Answer will be A
Hope it helps!

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n=(1/n)^n for all integers n > 0 [#permalink] New post   09 Jun 2023, 19:37
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If

\(\boxed {n} = (\frac{1}{n})^n\)

then

\(\boxed {3} = (\frac{1}{3})^3\)

\(\boxed {3} = \frac{1^3}{3^3}\)

\(\boxed {3} = \frac{1}{27}\)

Therefore, the Answer is Choice A
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n=(1/n)^n for all integers n > 0 [#permalink]
09 Jun 2023, 19:37
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