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2^x + 2^x
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09 May 2015, 10:27
09 May 2015, 10:27
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Question Stats:
65% (00:24) correct
34% (00:18) wrong based on 110 sessions
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\(2^x + 2^x\)
(A) \(2^{x+1}\)
(B) \(2^{x+2}\)
(C) \(2^{2x}\)
(D) \(4^{x}\)
(E) \(4^{2x}\)
Kudos for the right answer and explanation
(A) \(2^{x+1}\)
(B) \(2^{x+2}\)
(C) \(2^{2x}\)
(D) \(4^{x}\)
(E) \(4^{2x}\)
Kudos for the right answer and explanation
Re: GRE Math Challenge #85-Simplify 2^x + 2^x
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14 Dec 2017, 08:58
14 Dec 2017, 08:58
3
sandy wrote:
\(2^x + 2^x\)
(A) \(2^{x+1}\)
(B) \(2^{x+2}\)
(C) \(2^{2x}\)
(D) \(4^{x}\)
(E) \(4^{2x}\)
(A) \(2^{x+1}\)
(B) \(2^{x+2}\)
(C) \(2^{2x}\)
(D) \(4^{x}\)
(E) \(4^{2x}\)
Here
\(2^x + 2^x\) = \(2^{x+1}\)
This can also be proved
by taking x = 3
then \(2^3 + 2^3\) =\((2^3)\) * \(2^1\) = 16 i.e \(2^{3 + 1}\)
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Re: GRE Math Challenge #85-Simplify 2^x + 2^x
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14 Dec 2017, 10:18
14 Dec 2017, 10:18
2
sandy wrote:
\(2^x + 2^x\)
(A) \(2^{x+1}\)
(B) \(2^{x+2}\)
(C) \(2^{2x}\)
(D) \(4^{x}\)
(E) \(4^{2x}\)
(A) \(2^{x+1}\)
(B) \(2^{x+2}\)
(C) \(2^{2x}\)
(D) \(4^{x}\)
(E) \(4^{2x}\)
We can combine the terms in the same way we combine any like terms.
For example, k + k = 2k
And w² + w² = 2(w²)
And 3q³ + 3q³ = 2(3q³) = 6q³
Likewise, 2^x + 2^x = (2)2^x
= (2^1)(2^x)
= 2^(x + 1) [after we apply the product law]
Answer: A
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