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The average (arithmetic mean) cost per hinge for 16 hinges t
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22 Nov 2017, 19:09
22 Nov 2017, 19:09
1
Expert Reply
00:00
Question Stats:
73% (00:46) correct
26% (01:02) wrong based on 76 sessions
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Quantity A |
Quantity B |
The average (arithmetic mean) cost per hinge for 16 hinges that cost a total of 2p cents |
The average (arithmetic mean) cost per hinge for 4 hinges that cost a total of \(\frac{p}{2}\) cents |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Drill 2
Question: 10
Page: 526
Question: 10
Page: 526
Re: The average (arithmetic mean) cost per hinge for 16 hinges t
[#permalink]
08 Dec 2017, 06:57
08 Dec 2017, 06:57
1
Hi,
For QA
Cost per hinge is as follows
16/2p which is 8/p
For QB
Cost per hinge is 4/p÷2 which is 8/p
So C
For QA
Cost per hinge is as follows
16/2p which is 8/p
For QB
Cost per hinge is 4/p÷2 which is 8/p
So C
Re: The average (arithmetic mean) cost per hinge for 16 hinges t
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29 Dec 2017, 14:06
29 Dec 2017, 14:06
Expert Reply
Explanation
Plug in a value for p. Try p = 16: In Quantity A, then 16 hinges cost a total of 32 cents, for an average cost of 2 cents per hinge; in Quantity B, 4 hinges cost a total of 8 cents, for, again, an average cost of 2 cents per hinge.
The quantities are equal, so eliminate choices (A) and (B). Any value for p will yield the same results: The quantities will always equal; the
answer is choice C.
Plug in a value for p. Try p = 16: In Quantity A, then 16 hinges cost a total of 32 cents, for an average cost of 2 cents per hinge; in Quantity B, 4 hinges cost a total of 8 cents, for, again, an average cost of 2 cents per hinge.
The quantities are equal, so eliminate choices (A) and (B). Any value for p will yield the same results: The quantities will always equal; the
answer is choice C.
