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Re: In a garden, there are only red, yellow, and blue flowers. [#permalink]
1
Answer: B
red, yellow, blue flowers
1/3 * total = red
40/100 * total = blue = 2/5 * total
So yellow = total - red - blue = total - 1/3 * total - 4/10 * total = (30-10-12)/ 30 * total = 8/30 *total = 4/15*total

One flower is chosen at random.
A: The probability that the flower chosen is not red: So it can be either blue or yellow:
p(not red) = p(blue + yellow) = p(blue) + p(yellow) = 2/5 * total + 4/15 * total = 2/3 * total

B: The probability that the flower chosen is not yellow. So it can be either blue or red:
p(not yellow) = p(blue + red) = p(blue) + p(red) = 2/5 * total + 1/3 * total = 11/15* total

B is bigger than A. Answer is B.
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Re: In a garden, there are only red, yellow, and blue flowers. [#permalink]
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the lcm(3,5) is 15, let's write the given fractions in 15th:

r = 1/3 =5/15
b = 0.4 = 4/10 = 2/5 = 6/15
y = 1 - (r+b) = 4/15

Hence, A = 1 - r = 10/15 while B = 1 - y = 11/15

Answer B.

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Re: In a garden, there are only red, yellow, and blue flowers. [#permalink]
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Re: In a garden, there are only red, yellow, and blue flowers. [#permalink]
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