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If the graph of y = f(x) is shown above and g(x) = -f(x - 1), what i

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If the graph of y = f(x) is shown above and g(x) = -f(x - 1), what i [#permalink] New post   31 Jan 2022, 08:35
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GRE If the graph of y = f(x).jpg
GRE If the graph of y = f(x).jpg [ 11.1 KiB | Viewed 2066 times ]



If the graph of \(y = f(x)\) is shown above and \(g(x) = -f(x - 1) + 1\), what is the value of \(g(2)\)?

(A) -2

(B) -1

(C) 0

(D) 1

(E) 2
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B
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Re: If the graph of y = f(x) is shown above and g(x) = -f(x - 1), what i [#permalink] New post   10 Mar 2022, 02:56
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Re: If the graph of y = f(x) is shown above and g(x) = -f(x - 1), what i [#permalink] New post   14 Mar 2022, 02:19
Could you please explain how is it -1?
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Re: If the graph of y = f(x) is shown above and g(x) = -f(x - 1), what i [#permalink] New post   14 Mar 2022, 02:42
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OE

\(g(2) = -f(2 - 1) + 1 = -f(1) - 1 \)

Since \(f(1) = 0,

g(2) = 0 - 1 = -1.\)
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Re: If the graph of y = f(x) is shown above and g(x) = -f(x - 1), what i [#permalink] New post   18 Mar 2022, 09:03
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Re: If the graph of y = f(x) is shown above and g(x) = -f(x - 1), what i [#permalink] New post   24 Aug 2022, 06:30
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Carcass wrote:
OE

\(g(2) = -f(2 - 1) + 1 = -f(1) - 1 \)

Since \(f(1) = 0,

g(2) = 0 - 1 = -1.\)


I am stuck at -f(1)+1 = -f(1)-1, could you please explain
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If the graph of y = f(x) is shown above and g(x) = -f(x - 1), what i [#permalink] New post   24 Aug 2022, 09:53
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Carcass wrote:
Attachment:
GRE If the graph of y = f(x).jpg



If the graph of \(y = f(x)\) is shown above and \(g(x) = -f(x - 1) + 1\), what is the value of \(g(2)\)?

(A) -2

(B) -1

(C) 0

(D) 1

(E) 2


\(g(2) = -f(2 - 1) + 1 = -f(1) + 1 \) Note, in the OE, it seems the addition symbol turned into a subtraction symbol

Since \(f(1) = 0\), we get: \(g(2) = 0 + 1 = 1.\)

Answer: D
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Re: If the graph of y = f(x) is shown above and g(x) = -f(x - 1), what i [#permalink] New post   09 Dec 2023, 01:30
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\(g(x) = -f(x - 1) + 1\)

=> g(2) = -f(2-1) +1 = -f(1) + 1

y = f(x)
=> f(1) will be the value of y in the given figure when x = 1 which is 0
As the graph passes through the point (1,0)
=> f(1) = y = 0

=> g(2) = -0 + 1 = 1

So, Answer will be D
Hope it helps!

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