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If the sum of the reciprocals of two consecutive odd integers is 12/35
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25 Aug 2022, 09:44
25 Aug 2022, 09:44
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If the sum of the reciprocals of two consecutive odd integers is 12/35 then the greater of the two integers is
A. 3
B. 5
C. 7
D. 9
E. 11
A. 3
B. 5
C. 7
D. 9
E. 11
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
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GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
Re: If the sum of the reciprocals of two consecutive odd integers is 12/35
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25 Aug 2022, 10:18
25 Aug 2022, 10:18
1
Given for an odd integer x, 1/x +1/x+1 = 12/35
= 1/x+1 = 12/35 - 1/x
We can start from the answer choices here. For each choice, subtract it from 12/35 to see if you get the next integer
A. For 3, expected answer is 5 or 1, 12/35 - 1/3 = 1/35 *3 -> Not 5
B. For 5, expected answer is 7 or 3, 12/35 - 1/5 = 7
Can evaluate for others in the similar fashion.
Thus, Answer is C
= 1/x+1 = 12/35 - 1/x
We can start from the answer choices here. For each choice, subtract it from 12/35 to see if you get the next integer
A. For 3, expected answer is 5 or 1, 12/35 - 1/3 = 1/35 *3 -> Not 5
B. For 5, expected answer is 7 or 3, 12/35 - 1/5 = 7
Can evaluate for others in the similar fashion.
Thus, Answer is C
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Re: If the sum of the reciprocals of two consecutive odd integers is 12/35
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25 Aug 2022, 10:49
25 Aug 2022, 10:49
1
Carcass wrote:
If the sum of the reciprocals of two consecutive odd integers is 12/35 then the greater of the two integers is
A. 3
B. 5
C. 7
D. 9
E. 11
A. 3
B. 5
C. 7
D. 9
E. 11
Since the denominator of the sum is 35, and since 35 equals the product of 5 and 7 (two consecutive odd integers), let's start by testing whether 5 and 7 are the integers in question.
So, the RECIPROCALS are 1/5 and 1/7
1/5 + 1/7 = 7/35 + 5/35
= 12/35
Voila!!
So, the odd integers are 5 and 7
The greater of the two integers is 7
Answer: C
