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A coin is tossed 3 times.

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A coin is tossed 3 times. [#permalink] New post   26 Aug 2022, 04:55
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A coin is tossed 3 times.


Quantity A
Quantity B
the number of possible outcomes containing exactly 2 heads
the number of possible outcomes containing exactly 1 tail



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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C
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eligold
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Re: A coin is tossed 3 times. [#permalink] New post   26 Aug 2022, 07:06
1
Do not evaluate, first what is asked in both quantities
Quantity A -
Getting 2 heads exactly , that means third one has to be tails
There are 3!/2! permutations of the same = So, total 3 different ways of getting 2 heads (HHT/THH/HTH)

Quantity B
Getting 1 tails exactly , that means other two have to be heads
HHT - There are 3!/2! permutations of the same = So, total 3 different ways of getting 1 tail (HHT/THH/HTH)

Same outcomes in A and B;
Quantity A = Quantity B
Answer is C
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A coin is tossed 3 times. [#permalink] New post   23 Oct 2022, 09:44
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Given that A coin is tossed 3 times.

Coin is tossed 3 times => Total number of cases = \(2^3\) = 8

Quantity A: The number of possible outcomes containing exactly 2 heads

Out of the 8 outcomes there are only 3 outcomes in which we get exactly 2 Heads (or 1 Tail) and they are HHT, HTH, THH

Quantity B: The number of possible outcomes containing exactly 1 tail

Out of the 8 outcomes there are only 3 outcomes in which we get exactly 1 Tail (or 2 Heads) and they are HHT, HTH, THH

Clearly, Quantity A = Quantity B = 3

So, Answer will be C
Hope it helps!

Watch the following video to learn How to Solve Probability with Coin Toss Problems

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gmatclubot
A coin is tossed 3 times. [#permalink]
23 Oct 2022, 09:44
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