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F = {28, 29, 30, 31, 32} G = {10, 20, 30, 40, 50}
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26 Aug 2022, 04:51
26 Aug 2022, 04:51
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F = {28, 29, 30, 31, 32}
G = {10, 20, 30, 40, 50}
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
G = {10, 20, 30, 40, 50}
Quantity A |
Quantity B |
the mean of set F |
the median of set G |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
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GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
Re: F = {28, 29, 30, 31, 32} G = {10, 20, 30, 40, 50}
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26 Aug 2022, 07:13
26 Aug 2022, 07:13
1
F = {28, 29, 30, 31, 32}
F is a set of consecutive integers; Mean = Median = 30
G = {10, 20, 30, 40, 50}
Subtract 10 from each element in Set G to get Set X: {1, 2, 3, 4, 5} -> Set of consecutive integers; Mean = Median = 3
To transform Set X to Set G, add 10 back to each element, 10 will also get added to the mean and median. So, Mean = 30
Since both quantities are equal; Answer is C
F is a set of consecutive integers; Mean = Median = 30
G = {10, 20, 30, 40, 50}
Subtract 10 from each element in Set G to get Set X: {1, 2, 3, 4, 5} -> Set of consecutive integers; Mean = Median = 3
To transform Set X to Set G, add 10 back to each element, 10 will also get added to the mean and median. So, Mean = 30
Since both quantities are equal; Answer is C
gmatclubot
Re: F = {28, 29, 30, 31, 32} G = {10, 20, 30, 40, 50} [#permalink]
26 Aug 2022, 07:13
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