Area of a circle = \(πr^2 = \frac{π}{4}d^2\)
Area of a square = \(side^2\)

For Col. A, Area = \(\frac{π}{4}8^2 = 16π\)

For Col. B, area of the largest circle that could be cut out of a square would have its diamter as the side of square (side = 4)
i.e. d = 4
Area = \(\frac{π}{4}4^2 = 4π\)

Col. A: 16π
Col. B: 4π

Col. A > Col. B
Hence, option A