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A circular apple pie with a circumference of 18 is cut into 9 equal s

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Carcass
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A circular apple pie with a circumference of 18 is cut into 9 equal s [#permalink] New post   25 Aug 2022, 10:06
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A circular apple pie with a circumference of 18″ is cut into 9 equal slices. The slices are all cut starting at the center of the pie out to the edge of the crust.


Quantity A
Quantity B
the length of the arc formed by the crust of one slice at its outer edge
1.5″




A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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A
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Re: A circular apple pie with a circumference of 18 is cut into 9 equal s [#permalink] New post   03 Sep 2022, 09:01
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Carcass wrote:
A circular apple pie with a circumference of 18″ is cut into 9 equal slices. The slices are all cut starting at the center of the pie out to the edge of the crust.


Quantity A
Quantity B
the length of the arc formed by the crust of one slice at its outer edge
1.5″




A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given



Circumference of pie = \(18 = 2πr\)

The length of the arc formed by the crust of one slice at its outer edge would be \((1/9)^{th}\) of the total circumference

Col. A: \(\frac{2πr}{9}\)
Col. B: \(1.5\)

Multiplying both sides by 9;

Col. A: \(2πr\)
Col. B: (1.5)(9)

Col. A: \(18\)
Col. B: \(13.5\)

Col. A > Col. B
Hence, option A
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Re: A circular apple pie with a circumference of 18 is cut into 9 equal s [#permalink] New post   05 Sep 2022, 15:48
Any other solution on this?
Prep Club for GRE Bot
gmatclubot
Re: A circular apple pie with a circumference of 18 is cut into 9 equal s [#permalink]
05 Sep 2022, 15:48
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