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The function f is defined for each positive three-digit integer n by
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29 Aug 2022, 04:15
29 Aug 2022, 04:15
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62% (02:58) correct
37% (03:09) wrong based on 8 sessions
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The function f is defined for each positive three-digit integer n by \(f(n) = 2^x3^y5^z\) , where x, y and z are the hundreds, tens, and units digits of n, respectively. If m and v are three-digit positive integers such that \(f(m)=9*f(v)\) , then \(m-v=\) ?
Show: ::
20
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
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Re: The function f is defined for each positive three-digit integer n by
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04 Sep 2022, 22:45
04 Sep 2022, 22:45
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Carcass wrote:
The function f is defined for each positive three-digit integer n by \(f(n) = 2^x3^y5^z\) , where x, y and z are the hundreds, tens, and units digits of n, respectively. If m and v are three-digit positive integers such that \(f(m)=9*f(v)\) , then \(m-v=\) ?
Show: ::
20
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
n = xyz
\(f(n) = 2^x3^y5^z\)
Let m = abc and v = efg
then, \(f(m) = 2^a3^b5^c\)
\(f(v) = 2^e3^f5^g\)
We are given, \(f(m)=9*f(v) = 3^2 f(v)\)
i.e. \(2^a3^b5^c = 2^e3^{f+2}5^g\)
Using the property of exponents - When the bases are equal, then the powers are also equal. We have,
a = e
b = f+2
c = g
So, m - v = 020
Hence, the difference is 20
Re: The function f is defined for each positive three-digit integer n by
[#permalink]
13 Jul 2025, 06:31
13 Jul 2025, 06:31
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