GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If the average (arithmetic mean) of 3 distinct integers is 3
[#permalink]
24 Feb 2020, 16:14
24 Feb 2020, 16:14
1
2
Bookmarks
00:00
Question Stats:
44% (01:21) correct
55% (01:14) wrong based on 86 sessions
Hide Show timer Statistics
If the average (arithmetic mean) of 3 distinct integers is 37, and the least integer is 18, which of the following could be the greatest integer?
a. 40
b. 46
c. 49
d. 58
e. 74
f. 77
a. 40
b. 46
c. 49
d. 58
e. 74
f. 77
Re: If the average (arithmetic mean) of 3 distinct integers is 3
[#permalink]
24 Feb 2020, 22:35
24 Feb 2020, 22:35
3
The total of integers should be 111. Now, 18 the least of all. Hence, the sum of other two integers must be 93. Now, options A and B aren't possible as they won't make the the integer greatest. Also, option E , if chosen would make the third integer as 16 which is smaller than the least integer given as 18. Hence,eliminate option E. So, only C,D,E conform to the given conditions.
Re: If the average (arithmetic mean) of 3 distinct integers is 3
[#permalink]
12 Nov 2020, 03:53
12 Nov 2020, 03:53
1
the sum of three numbers= 37*3=111
as the numbers are distinct, the lowest number is given= 18
the next lower number=19
so, the greatest possible number= 111-(18+19)= 74 (answer E)
as the numbers are distinct, the lowest number is given= 18
the next lower number=19
so, the greatest possible number= 111-(18+19)= 74 (answer E)
