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A coin is tossed 3 times.
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29 Aug 2022, 03:24
29 Aug 2022, 03:24
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Question Stats:
94% (00:35) correct
5% (00:41) wrong based on 19 sessions
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A coin is tossed 3 times.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
the probability of tossing 3 tails |
1/2 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
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Re: A coin is tossed 3 times.
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06 Sep 2022, 12:26
06 Sep 2022, 12:26
1
Carcass wrote:
A coin is tossed 3 times.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
the probability of tossing 3 tails |
1/2 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials (2022)
GRE Geometry Formulas
GRE - Math Book
Total number of outcomes in case of coin problem = \(2^n\)
where, n is number of times it is tossed
Here, Total outcomes = \(2^3\) = 8
Now, we have only one case with all three Tails i.e. TTT
So, reqd. prob. = \(\frac{1}{8}\)
Col. A: \(\frac{1}{8}\)
Col. B: \(\frac{1}{2}\)
Col. A < Col. B
Hence, option B
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A coin is tossed 3 times.
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23 Oct 2022, 10:09
23 Oct 2022, 10:09
1
Given that A coin is tossed 3 times.
Coin is tossed 3 times => Total number of cases = \(2^3\) = 8
Quantity A: The probability of tossing 3 tails
Out of the 8 outcomes there is only one case in which we get 3 Tails (TTT).
=> The probability of tossing 3 tails = \(\frac{1}{8}\)
Clearly, Quantity B(\(\frac{1}{2}\)) > Quantity A(\(\frac{1}{8}\))
So, Answer will be B
Hope it helps!
Watch the following video to learn How to Solve Probability with Coin Toss Problems
Coin is tossed 3 times => Total number of cases = \(2^3\) = 8
Quantity A: The probability of tossing 3 tails
Out of the 8 outcomes there is only one case in which we get 3 Tails (TTT).
=> The probability of tossing 3 tails = \(\frac{1}{8}\)
Clearly, Quantity B(\(\frac{1}{2}\)) > Quantity A(\(\frac{1}{8}\))
So, Answer will be B
Hope it helps!
Watch the following video to learn How to Solve Probability with Coin Toss Problems
