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A bus leaves the station traveling at a constant speed of 45 miles pe
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24 May 2022, 16:06
24 May 2022, 16:06
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Question Stats:
87% (01:35) correct
12% (01:42) wrong based on 32 sessions
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A bus leaves the station traveling at a constant speed of 45 miles per hour. A second bus leaves the same station heading in the same direction one hour later traveling at a constant speed of 50 miles per hour.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
The number of hours after the first bus left that the buses will pass each other |
8 hours |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
Re: A bus leaves the station traveling at a constant speed of 45 miles pe
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24 May 2022, 23:49
24 May 2022, 23:49
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This question can be solved quickly using relative speed. The relative speed of the bus B(second bus) wrt A is 50-45= 5 mph(as both travel in the same direction)
The distance between them is 45 miles as the first bus covers that much in an hour while the second bus was stationary.
Hence the time taken by the second bus to bridge this gap is given by {total distance to be covered/relative speed}
Therefore 45/5=9 hrs. So in 9hrs both busses will meet and post that B crosses A.
Quantity A is greater and hence Option A is the answer.
The distance between them is 45 miles as the first bus covers that much in an hour while the second bus was stationary.
Hence the time taken by the second bus to bridge this gap is given by {total distance to be covered/relative speed}
Therefore 45/5=9 hrs. So in 9hrs both busses will meet and post that B crosses A.
Quantity A is greater and hence Option A is the answer.
Re: A bus leaves the station traveling at a constant speed of 45 miles pe
[#permalink]
09 Sep 2022, 09:08
09 Sep 2022, 09:08
2
123444 wrote:
This question can be solved quickly using relative speed. The relative speed of the bus B(second bus) wrt A is 50-45= 5 mph(as both travel in the same direction)
The distance between them is 45 miles as the first bus covers that much in an hour while the second bus was stationary.
Hence the time taken by the second bus to bridge this gap is given by {total distance to be covered/relative speed}
Therefore 45/5=9 hrs. So in 9hrs both busses will meet and post that B crosses A.
Quantity A is greater and hence Option A is the answer.
The distance between them is 45 miles as the first bus covers that much in an hour while the second bus was stationary.
Hence the time taken by the second bus to bridge this gap is given by {total distance to be covered/relative speed}
Therefore 45/5=9 hrs. So in 9hrs both busses will meet and post that B crosses A.
Quantity A is greater and hence Option A is the answer.
A less intuitive way to solve it, is recognizing that both buses will travel the same distance if they meet each other. Therefore, setting up the euation, we have:
\(45(h+1) = 50h\)
with h = 9.
Ans A
