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The average (arithmetic mean) of fifteen consecutive integer
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29 Aug 2018, 16:40
29 Aug 2018, 16:40
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80% (01:28) correct
20% (01:41) wrong based on 40 sessions
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The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?
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95
Re: The average (arithmetic mean) of fifteen consecutive integer
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30 Aug 2018, 01:08
30 Aug 2018, 01:08
2
1st number = x
2nd number = x+1
3rd number = x+2
15th number = x+14
avg = \(\frac{x+14+x}{2} = 88\)
or, \(\frac{2x+14}{2} = 88\)
or, \(x+7 = 88\)
or, \(x = 81\)
since the largest number is \(x+14\) it is 81 + 14 = 95
2nd number = x+1
3rd number = x+2
15th number = x+14
avg = \(\frac{x+14+x}{2} = 88\)
or, \(\frac{2x+14}{2} = 88\)
or, \(x+7 = 88\)
or, \(x = 81\)
since the largest number is \(x+14\) it is 81 + 14 = 95
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Re: The average (arithmetic mean) of fifteen consecutive integer
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16 Sep 2022, 22:58
16 Sep 2022, 22:58
2
Given that The average (arithmetic mean) of fifteen consecutive integers is 88 and we need to find the greatest of these integers
============================================================
Theory
============================================================
Let the middle term be x
=> Mean = middle term = x = 88
Now, the numbers are consecutive so the greatest or the last term will be 7 more than the middle term = x + 7 = 88 + 7 = 95
So, Answer will be 95.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
============================================================
Theory
- ‣‣‣ In Case of consecutive number Mean = Middle term
============================================================
Let the middle term be x
=> Mean = middle term = x = 88
Now, the numbers are consecutive so the greatest or the last term will be 7 more than the middle term = x + 7 = 88 + 7 = 95
So, Answer will be 95.
Hope it helps!
Watch the following video to Learn the Basics of Statistics
