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If 3p = 4s, 5s = 3/r, and r 0, what is r in terms of p?
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26 Jun 2022, 22:50
26 Jun 2022, 22:50
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If \(3p = 4s, \ 5s = \frac{3}{r}\), and \(r ≠ 0\), what is r in terms of p?
A. \(\frac{4}{5p}\)
B. \(\frac{4p}{5}\)
C. \(\frac{5p}{4}\)
D. \(\frac{9}{20p}\)
E. \(\frac{45}{4p}\)
A. \(\frac{4}{5p}\)
B. \(\frac{4p}{5}\)
C. \(\frac{5p}{4}\)
D. \(\frac{9}{20p}\)
E. \(\frac{45}{4p}\)
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Joined: 10 Apr 2015
Posts: 6218
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Re: If 3p = 4s, 5s = 3/r, and r 0, what is r in terms of p?
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27 Jun 2022, 06:29
27 Jun 2022, 06:29
1
GeminiHeat wrote:
If \(3p = 4s, \ 5s = \frac{3}{r}\), and \(r ≠ 0\), what is r in terms of p?
A. \(\frac{4}{5p}\)
B. \(\frac{4p}{5}\)
C. \(\frac{5p}{4}\)
D. \(\frac{9}{20p}\)
E. \(\frac{45}{4p}\)
A. \(\frac{4}{5p}\)
B. \(\frac{4p}{5}\)
C. \(\frac{5p}{4}\)
D. \(\frac{9}{20p}\)
E. \(\frac{45}{4p}\)
One approach is to rewrite each equation so that they both feature the same multiple of \(s\). Here's what I mean:
Take: \(3p = 4s\)
Create an equivalent equation by multiplying both sides by \(5\) to get: \(15p = 20s\)
Take: \(5s = \frac{3}{r}\)
Create an equivalent equation by multiplying both sides by \(4\) to get: \(20s = \frac{12}{r}\)
Since both equations are set equal to \(20s\), we can create the following equation: \(15p = \frac{12}{r}\)
Multiply both sides of the equation by \(r\) to get: \(15pr = 12\)
Divide both sides of the equation by \(15p\) to get: \(r = \frac{12}{15p}= \frac{4}{5p}\)
Answer: A
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If 3p = 4s, 5s = 3/r, and r 0, what is r in terms of p?
[#permalink]
20 Sep 2022, 05:32
20 Sep 2022, 05:32
Given that 3p = 4s and 5s = \(\frac{3}{r}\) and r ≠ 0 and we need to find what is r in terms of p
3p = 4s
=> 4s = 3p and
5s = \(\frac{3}{r}\)
Dividing above two equation we get
\(\frac{4s}{5s}\) = 3p / (\(\frac{3}{r}\))
=> \(\frac{4}{5}\) = p*r
=> r = \(\frac{4}{5p}\)
So, Answer will be A
Hope it helps!
3p = 4s
=> 4s = 3p and
5s = \(\frac{3}{r}\)
Dividing above two equation we get
\(\frac{4s}{5s}\) = 3p / (\(\frac{3}{r}\))
=> \(\frac{4}{5}\) = p*r
=> r = \(\frac{4}{5p}\)
So, Answer will be A
Hope it helps!
