GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
An electric company charges $a for the first 100 kw of electricity use
[#permalink]
25 Sep 2022, 01:53
25 Sep 2022, 01:53
Expert Reply
00:00
Question Stats:
66% (01:12) correct
33% (01:09) wrong based on 3 sessions
Hide Show timer Statistics
An electric company charges $a for the first 100 kw of electricity used and $p for each additional kw used. If the total electricity bill for a particular month was $100, what was the total amount of electricity used in that month?
A. \(\frac{(100+100p)}{(p-a)}\)
B. \(\frac{100+100p-a}{p}\)
C. \(\frac{100+100p-a}{100p}
\)
D. \(\frac{100p-a}{p}
\)
E. \(\frac{100p-a}{100p}
\)
A. \(\frac{(100+100p)}{(p-a)}\)
B. \(\frac{100+100p-a}{p}\)
C. \(\frac{100+100p-a}{100p}
\)
D. \(\frac{100p-a}{p}
\)
E. \(\frac{100p-a}{100p}
\)
Part of the Skill Builder Project
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials
GRE Geometry Formulas
GRE - Math Book
Show: ::
variable in the answer choices
Moderator
Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1131
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
Re: An electric company charges $a for the first 100 kw of electricity use
[#permalink]
28 Sep 2022, 09:33
28 Sep 2022, 09:33
2
Given that An electric company charges $a for the first 100 kw of electricity used and $p for each additional kw used. If the total electricity bill for a particular month was $100. And we need to find what was the total amount of electricity used in that month
Let the total amount of electricity used be (100 + x) kw
=> Total bill will be $a (for first 100 kw) + $p*x (for additional x kw)
=> Total bill = a + px = 100 (given)
=> x = \(\frac{100 - a}{p}\)
=> Total amount of electricity used = 100 + x = 100 + \(\frac{100 - a}{p}\) = \(\frac{100+100p-a}{p}\)
So, Answer will be B
Hope it helps!
Let the total amount of electricity used be (100 + x) kw
=> Total bill will be $a (for first 100 kw) + $p*x (for additional x kw)
=> Total bill = a + px = 100 (given)
=> x = \(\frac{100 - a}{p}\)
=> Total amount of electricity used = 100 + x = 100 + \(\frac{100 - a}{p}\) = \(\frac{100+100p-a}{p}\)
So, Answer will be B
Hope it helps!
Re: An electric company charges $a for the first 100 kw of electricity use
[#permalink]
28 Sep 2022, 20:03
28 Sep 2022, 20:03
1
[quote="BrushMyQuant"]Given that An electric company charges $a for the first 100 kw of electricity used and $p for each additional kw used. If the total electricity bill for a particular month was $100. And we need to find what was the total amount of electricity used in that month
Let the total amount of electricity used be (100 + x) kw
=> Total bill will be $a (for first 100 kw) + $p*x (for additional x kw)
=> Total bill = a + px = 100 (given)
=> x = \(\frac{100 - a}{p}\)
=> Total amount of electricity used = 100 + x = 100 + \(\frac{100 - a}{p}\) = \(\frac{100+100p-a}{p}\)
Where do the extra P and A come from in the bolded section?
Let the total amount of electricity used be (100 + x) kw
=> Total bill will be $a (for first 100 kw) + $p*x (for additional x kw)
=> Total bill = a + px = 100 (given)
=> x = \(\frac{100 - a}{p}\)
=> Total amount of electricity used = 100 + x = 100 + \(\frac{100 - a}{p}\) = \(\frac{100+100p-a}{p}\)
Where do the extra P and A come from in the bolded section?
