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An electric company charges $a for the first 100 kw of electricity use
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25 Sep 2022, 01:53
25 Sep 2022, 01:53
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66% (01:12) correct
33% (01:09) wrong based on 3 sessions
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An electric company charges $a for the first 100 kw of electricity used and $p for each additional kw used. If the total electricity bill for a particular month was $100, what was the total amount of electricity used in that month?
A. \(\frac{(100+100p)}{(p-a)}\)
B. \(\frac{100+100p-a}{p}\)
C. \(\frac{100+100p-a}{100p}
\)
D. \(\frac{100p-a}{p}
\)
E. \(\frac{100p-a}{100p}
\)
A. \(\frac{(100+100p)}{(p-a)}\)
B. \(\frac{100+100p-a}{p}\)
C. \(\frac{100+100p-a}{100p}
\)
D. \(\frac{100p-a}{p}
\)
E. \(\frac{100p-a}{100p}
\)
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variable in the answer choices
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Re: An electric company charges $a for the first 100 kw of electricity use
[#permalink]
28 Sep 2022, 09:33
28 Sep 2022, 09:33
2
Given that An electric company charges $a for the first 100 kw of electricity used and $p for each additional kw used. If the total electricity bill for a particular month was $100. And we need to find what was the total amount of electricity used in that month
Let the total amount of electricity used be (100 + x) kw
=> Total bill will be $a (for first 100 kw) + $p*x (for additional x kw)
=> Total bill = a + px = 100 (given)
=> x = \(\frac{100 - a}{p}\)
=> Total amount of electricity used = 100 + x = 100 + \(\frac{100 - a}{p}\) = \(\frac{100+100p-a}{p}\)
So, Answer will be B
Hope it helps!
Let the total amount of electricity used be (100 + x) kw
=> Total bill will be $a (for first 100 kw) + $p*x (for additional x kw)
=> Total bill = a + px = 100 (given)
=> x = \(\frac{100 - a}{p}\)
=> Total amount of electricity used = 100 + x = 100 + \(\frac{100 - a}{p}\) = \(\frac{100+100p-a}{p}\)
So, Answer will be B
Hope it helps!
Re: An electric company charges $a for the first 100 kw of electricity use
[#permalink]
28 Sep 2022, 20:03
28 Sep 2022, 20:03
1
[quote="BrushMyQuant"]Given that An electric company charges $a for the first 100 kw of electricity used and $p for each additional kw used. If the total electricity bill for a particular month was $100. And we need to find what was the total amount of electricity used in that month
Let the total amount of electricity used be (100 + x) kw
=> Total bill will be $a (for first 100 kw) + $p*x (for additional x kw)
=> Total bill = a + px = 100 (given)
=> x = \(\frac{100 - a}{p}\)
=> Total amount of electricity used = 100 + x = 100 + \(\frac{100 - a}{p}\) = \(\frac{100+100p-a}{p}\)
Where do the extra P and A come from in the bolded section?
Let the total amount of electricity used be (100 + x) kw
=> Total bill will be $a (for first 100 kw) + $p*x (for additional x kw)
=> Total bill = a + px = 100 (given)
=> x = \(\frac{100 - a}{p}\)
=> Total amount of electricity used = 100 + x = 100 + \(\frac{100 - a}{p}\) = \(\frac{100+100p-a}{p}\)
Where do the extra P and A come from in the bolded section?
