Last visit was: 28 Nov 2024, 07:48 It is currently 28 Nov 2024, 07:48
Decision Tracker
My Rewards
New comers' posts
New posts
Unanswered

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more
Close

Request Expert Reply

Confirm Cancel
PREVIOUS TOPIC
NEXT TOPIC

-1<x<0

Tags :
Find Similar Topics  About  Add a Tag

Show Tags
Hide Tags

User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30050
Own Kudos [?]: 36459 [2]
Given Kudos: 25940
Send PM
-1<x<0 [#permalink] New post   01 Oct 2022, 09:57
Expert Reply
2
Bookmarks
00:00

Question Stats:

18% (00:37) correct 81% (00:39) wrong based on 44 sessions

Hide Show timer Statistics

\(-1<x<0\)


Quantity A
Quantity B
\(-x\)
\(-x^3\)



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


ShowHide Answer
Official Answer
B
avatar
B
kk117
Manager
Manager
Joined: 06 Jun 2021
Posts: 78
Own Kudos [?]: 13 [0]
Given Kudos: 61
Send PM
Re: -1<x<0 [#permalink] New post   03 Oct 2022, 10:08
Could someone please explain this question?

I got A as I divided both sides by (-x)

Hence,

A: 1
B: x^2

Now since x is less than 0 but greater than (-1), hence x^2 is less than (1)

Hence, A

But since the answer is B, what is wrong with my approach?
avatar
S
GREfocus
Intern
Intern
Joined: 17 Sep 2022
Posts: 48
Own Kudos [?]: 48 [1]
Given Kudos: 13
Send PM
Re: -1<x<0 [#permalink] New post   12 Oct 2022, 00:14
1
-1 < x <0 is basically saying
x= negative non integer or fraction
Let x= -1/2

Quantity A
-1/2 or -0.5

Quantity B
(-1/2)(-1/2)(-1/2) = -1/8 or -0.125

Quantity A is more negative than Quantity B
Hence B is greater

Posted from my mobile device
avatar
B
eywilson
Intern
Intern
Joined: 19 Jan 2023
Posts: 10
Own Kudos [?]: 4 [1]
Given Kudos: 25
Send PM
Re: -1<x<0 [#permalink] New post   01 Mar 2023, 12:48
1
GREfocus wrote:
-1 < x <0 is basically saying
x= negative non integer or fraction
Let x= -1/2

Quantity A
-1/2 or -0.5

Quantity B
(-1/2)(-1/2)(-1/2) = -1/8 or -0.125

Quantity A is more negative than Quantity B
Hence B is greater

Posted from my mobile device


GREfocus that's not correct though, because it's a double negative situation. You have to sub the variable into the x inside brackets. Since we're dealing with a negative fraction/non-integer, quantity A becomes -(-1/2) or 1/2 and B is -(-1/2)^3 = -(-1/8) = 1/8. Hence A should be bigger
avatar
sree94
Intern
Intern
Joined: 05 Mar 2023
Posts: 1
Own Kudos [?]: 2 [2]
Given Kudos: 0
Send PM
Re: -1<x<0 [#permalink] New post   06 Mar 2023, 14:58
2
here x is negative and the question gives -x, -x^3 which means double negative turns to be positive, so quantity A is bigger
Prep Club for GRE Bot
gmatclubot
Re: -1<x<0 [#permalink]
06 Mar 2023, 14:58
Moderators:
adewale223
GRE Instructor
86 posts
bronaugust
GRE Forum Moderator
37 posts
BrushMyQuant
Moderator
1111 posts
VibhuAnurag
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Main navigation

Partners

GRE Resources

www.ets.org/gre | About | Terms and Conditions and Privacy Policy | Prep Club for GRE Rules | Contact