Given that If a certain coin is flipped, the probability that the coin will land heads is 1/2. If the coin is flipped 5 times, and we need to find what is the probability that it will land heads up on the first 3 flips and not on the last 2 flips?

Coin is tossed 5 times => Total number of cases = \(2^5\) = 32

We need to get head in the first 3 flips and not in the last 2 flips => HHHTT

So, there is only one case out of 32 when this will happen.

=> P(HHHTT) = \(\frac{1}{32}\)

So, Answer will be E
Hope it helps!

Playlist on Solved Problems on Probability here

Watch the following video to MASTER Probability with Coin Toss Problems

Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.