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If 5a + 7b = k, where a and b are positive integers, what is the large [#permalink]
mandvi19

\(a\) and \(b\) are positive integers.


mandvi19 wrote:
The answer shown is D. however D can be arrived at with two possible values i.e. 5x0 + 7x10 and 5x7 + 7x5. However, the value B which is 48 can be arrived at only with the following - 5x4 + 7x4.
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Re: If 5a + 7b = k, where a and b are positive integers, what is the large [#permalink]
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GeminiHeat wrote:
+1 Kudos to posts containing answer with explanation


Given we want the biggest possible value of K, let’s go by options, and start with the biggest value

In options, we can check combination of factors as a case each


Example

For k = 74
74 = 37 x 2
In 5a + 7b, the end unit level should be 4. 5a will always end in 5 or 0.
Now if we consider these as cases,
Case 1 - 5a ends with 0
- then for 7b ends with 4 at 14 (7x2). In such a case the largest k value possible is 5x8 + 7x2 = 40 + 14 = 64. So not satisfied.
Case 2 - 5a end with 5
- then we need 7b to end in -1 or +9.
Since a = +ve, so -1 is ruled out.
7b ends with 9 at 49 (7x7). In such a case the largest k value possible is
5X1 + 7X7 = 5 + 49 = 54. So not satisfied.
5X3 + 7X7 = 15 + 49 = 64. So not satisfied.
5x5 + 7x7 = 25 + 49 = 94. So not satisfied.


For k = 70

70 = 14 x 5

Case 1
5a + 7b = 5 x7 + 7x 5 = 70 —-> so a=7, and b = 5, give k = 70. Which is the largest possible k value
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