\(\dfrac{Length of Arc PR}{Circumference of the Circle} = \dfrac{Angle of Arc}{Angle of Circumference} = \dfrac{60}{360} = \dfrac{1}{6}\)

The Length of Arc PR is \(\dfrac{1}{6}^{th}\) of Circumference of Circle

The Length of Arc PQR = \(1-\dfrac{1}{6} = \dfrac{5}{6}^{th}\) of Circumference of Circle

Since Circumference of the Circle is \(2 \pi r\)

Length of Arc PQR \(= 2 \pi r \times \dfrac{5}{6} = \dfrac{5 \pi r}{3}\)

Since \(r=2\) (given)

Length of Arc PQR \(= \dfrac{5 \pi 2}{3} = \dfrac{10 \pi}{3}\)

Now

\(\dfrac{10 \pi}{3} > 3 \pi\)

\(3.333 \pi > 3 \pi\)

Quantity A is the greatest.