Given:
- Two triangles $\(Q_1\)$ and $\(Q_2\)$ have equal areas
- Heights of $\(Q_1\)$ and $\(Q_2\)$ are $\(h_1\)$ and $\(h_2\)$, respectively

Step 1: Recall area formula for a triangle
Area of a triangle is given by:

$$
\(\text { Area }=\frac{1}{2} \times \text { base } \times \text { height }\)
$$


Step 2: Let bases be $b_1$ and $b_2$ for triangles $\(Q_1\)$ and $\(Q_2\)$, respectively
Since the areas are equal:

$$
\(\begin{aligned}
\frac{1}{2} b_1 h_1 & =\frac{1}{2} b_2 h_2 \\
b_1 h_1 & =b_2 h_2
\end{aligned}\)
$$


Step 3: Relate $\(h_1\)$ and $\(h_2\)$
From the equation,

$$
\(h_1=\frac{b_2}{b_1} h_2\)
$$


Without knowing the relationship between $\(b_1\)$ and $\(b_2\)$, we cannot determine which height is larger or if they are equal.

Conclusion:
- The relationship between $\(h_1\)$ and $\(h_2\)$ cannot be determined without information about bases $\(b_1\)$ and $\(b_2\)$.
- The quantities $\(h_1\)$ and $\(h_2\)$ could be equal, $\(h_1>h_2\)$, or $\(h_1<h_2\)$, depending on the bases.

Hence, the answer is that the comparison cannot be determined from the given information.