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Quadrilateral ABCD is a rectangle.
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12 Nov 2017, 01:29
12 Nov 2017, 01:29
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Question Stats:
65% (01:20) correct
35% (00:47) wrong based on 20 sessions
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Quadrilateral ABCD is a rectangle.
Quantity A |
Quantity B |
\(\frac{AC}{AB}\) |
\(\frac{AB}{AD}\) |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
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Re: Quadrilateral ABCD is a rectangle.
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12 Nov 2017, 09:36
12 Nov 2017, 09:36
1
Remember that figures in GRE are not drawn to scale, so that, in this case, our rectangle can be shrunk or widened as we want.
Having said that, if our triangle were a square, then quantity A would have been \(\frac{\sqrt2 x}{x} = \sqrt2\) and quantity B \(\frac{x}{x} = 1\), so that A>B.
However, it can be the case that AB = 3, AD = 1 so that AC = \(\sqrt{10}\). In this case A = \(\frac{\sqrt{10}}{3} \sim 1\) while B = 3 so that A<B.
Answer D
Having said that, if our triangle were a square, then quantity A would have been \(\frac{\sqrt2 x}{x} = \sqrt2\) and quantity B \(\frac{x}{x} = 1\), so that A>B.
However, it can be the case that AB = 3, AD = 1 so that AC = \(\sqrt{10}\). In this case A = \(\frac{\sqrt{10}}{3} \sim 1\) while B = 3 so that A<B.
Answer D
Re: Quadrilateral ABCD is a rectangle.
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19 Jul 2025, 23:43
19 Jul 2025, 23:43
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