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Santa visited an orphanage housing 13 children.
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05 Mar 2021, 10:19
05 Mar 2021, 10:19
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Question Stats:
41% (02:51) correct
58% (02:33) wrong based on 148 sessions
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Santa visited an orphanage housing 13 children. He brought with him a total of n presents. Ensuring that each child received an equal number of presents, Santa returned to the North Pole with 11 undistributed presents.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The number of presents Santa would have come home with if the orphanage had 1 more child. |
The number of presents Santa would have come home with if the orphanage had 2 more children. |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: Santa visited an orphanage housing 13 children.
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06 Mar 2021, 02:32
06 Mar 2021, 02:32
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harishsridharan wrote:
Santa visited an orphanage housing 13 children. He brought with him a total of n presents. Ensuring that each child received an equal number of presents, Santa returned to the North Pole with 11 undistributed presents.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The number of presents Santa would have come home with if the orphanage had 1 more child. |
The number of presents Santa would have come home with if the orphanage had 2 more children. |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Remember, any number \(N\) when divided by divisor \(x\) can be written as \(xQ + R\)
Where, Q = quotient and R = remainder
Using the above logic, Number of Presents = \(13Q + 11\)
Let us assume Q = 1 and 10
Number of Presents then could be 24 and 141
Case I: \(P = 24\)
Col. A: on dividing 24 by 14, remainder is 10
Col. B: on dividing 24 by 15, remainder is 9
Col. A > Col. B
Case II: \(P = 141\)
Col. A: on dividing 141 by 14, remainder is 1
Col. B: on dividing 141 by 15, remainder is 6
Col. A < Col. B
Hence, option D
[NOTE: try to pick 2-3 values having a difference of 5-10 in between them]
General Discussion
Re: Santa visited an orphanage housing 13 children.
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05 Mar 2021, 19:58
05 Mar 2021, 19:58
D
Remainder theory, but it's time consuming cuz you have to try several values before getting B greater than A.
Remainder theory, but it's time consuming cuz you have to try several values before getting B greater than A.
