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Set M consists of 20 evenly spaced integers, 10 numbers of w
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30 Aug 2018, 07:38
30 Aug 2018, 07:38
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Question Stats:
41% (01:03) correct
59% (00:47) wrong based on 100 sessions
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Set M consists of 20 evenly spaced integers, 10 numbers of which are positive and 10 of which are negative.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The average (arithmetic mean) of all the numbers in set M |
\(0\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: Set M consists of 20 evenly spaced integers, 10 numbers of w
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30 Aug 2018, 10:04
30 Aug 2018, 10:04
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sandy wrote:
Set M consists of 20 evenly spaced integers, 10 numbers of which are positive and 10 of which are negative.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The average (arithmetic mean) of all the numbers in set M |
\(0\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Nice question!
ASIDE: I've never been a fan of the term "EVENLY spaced". I worry that students believe that the difference between consecutive values must be EVEN. SO, I typically write "EQUALLY spaced."
Okay, let's solve this question by coming up with some 20-number sets that satisfy the given conditions.
CASE A: The numbers are {-19, -17, -15, -13, -11, -9, -7, -5, -3, -1, 1, 3, 5, 7, 9, 11, 13, 15, 17, 19}
Here, the mean of the set is 0
So, in this case, the two quantities are EQUAL
CASE B: The numbers are {-28, -25, -22, -19, -16, -13, -10, -7, -4, -1, 2, 5, 8, 11, 14, 17, 20, 23, 26, 29}
Here, the mean of the set is NOT zero
So, in this case, the two quantities are NOT EQUAL
Answer: D
RELATED VIDEO FROM OUR COURSE
General Discussion
Re: Set M consists of 20 evenly spaced integers, 10 numbers of w
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14 Jan 2019, 01:38
14 Jan 2019, 01:38
Expert Reply
GreenlightTestPrep wrote:
sandy wrote:
Set M consists of 20 evenly spaced integers, 10 numbers of which are positive and 10 of which are negative.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The average (arithmetic mean) of all the numbers in set M |
\(0\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Nice question!
ASIDE: I've never been a fan of the term "EVENLY spaced". I worry that students believe that the difference between consecutive values must be EVEN. SO, I typically write "EQUALLY spaced."
Okay, let's solve this question by coming up with some 20-number sets that satisfy the given conditions.
CASE A: The numbers are {-19, -17, -15, -13, -11, -9, -7, -5, -3, -1, 1, 3, 5, 7, 9, 11, 13, 15, 17, 19}
Here, the mean of the set is 0
So, in this case, the two quantities are EQUAL
CASE B: The numbers are {-28, -25, -22, -19, -16, -13, -10, -7, -4, -1, 2, 5, 8, 11, 14, 17, 20, 23, 26, 29}
Here, the mean of the set is NOT zero
So, in this case, the two quantities are NOT EQUAL
Answer: D
RELATED VIDEO FROM OUR COURSE
Wow, great stuff.
