Carcass wrote:
Solve each of the following inequalities for x.
(a) \(−3x>7+x\)
(b) \(25x+16≥10−x\)
(c) \(16+x>8x−12\)
(a) \(x < -\frac{7}{4}\) (b) \(x \geq - \frac{3}{13}\) (c) \(x < 4\)
Math Review
Question:
Page: 244
Difficulty: medium
(a) \(−3x>7+x\)
Subtract x from both sides: \(−4x>7\)
Divide both sides by -4 to get: \(x<-\frac{7}{4}\)
(b) \(25x+16≥10−x\)
Add x to both sides:\(26x+16≥10\)
Subtract 16 from both sides: \(26x≥-6\)
Divide both sides by 26 to get: \(x ≥ -\frac{6}{26}\)
Simplify: \(x ≥ -\frac{3}{13}\)
(c) \(16+x>8x−12\)
Add 12 to both sides:\(28+x>8x\)
Subtract x from both sides: \(28>7x\)
Divide both sides by 7 to get: \(4>x\) or we can write \(x<4\)
Cheers,
Brent
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Brent Hanneson - founder of Greenlight Test Prep