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T (triple) = Three Users provided this score. D (double) = T
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07 Jun 2018, 09:24
07 Jun 2018, 09:24
Expert Reply
00:00
Question Stats:
80% (00:52) correct
20% (02:52) wrong based on 5 sessions
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stores.jpg [ 22.44 KiB | Viewed 2254 times ]
T (triple) = Three Users provided this score. D (double) = Two Users provided this score.
What was the average (arithmetic mean) rating for Readily available in stores among the items that were rated 8 for Durability?
A. 3
B. 4
C. 5
D. 6
E. 7
Re: T (triple) = Three Users provided this score. D (double) = T
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07 Jun 2018, 23:17
07 Jun 2018, 23:17
1
Carcass wrote:
Attachment:
stores.jpg
T (triple) = Three Users provided this score. D (double) = Two Users provided this score.
What was the average (arithmetic mean) rating for Readily available in stores among the items that were rated 8 for Durability?
A. 3
B. 4
C. 5
D. 6
E. 7
Just want to see whether my solution is correct.
Here for 8 durability , we have 8, 4 and 3 as the values.
Then to know AM = 8+4+3 / 3 = 15/3 = 5.
Answer C. I hope T and D not have any influence for this question, if yes then please do let me know.
T (triple) = Three Users provided this score. D (double) = T
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07 May 2019, 10:13
07 May 2019, 10:13
Expert Reply
Attachment:
#GREpracticequestion T (triple) = Three.jpg [ 28.21 KiB | Viewed 2374 times ]
T (triple) = Three Users provided this score. D (double) = Two Users provided this score.
What was the average (arithmetic mean) rating for Readily available in stores among the items that were rated 8 for Durability?
A. 3
B. 4
C. 5
D. 6
E. 7
