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Tarik has a pile of 6 green chips numbered 1 through 6 respe
[#permalink]
05 Aug 2018, 14:40
05 Aug 2018, 14:40
1
Expert Reply
00:00
Question Stats:
85% (00:52) correct
14% (00:22) wrong based on 147 sessions
Hide Show timer Statistics
Tarik has a pile of 6 green chips numbered 1 through 6 respectively and another pile of 6 blue chips numbered 1 through 6 respectively. Tarik will randomly pick 1 chip from
the green pile and 1 chip from the blue pile.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
the green pile and 1 chip from the blue pile.
Quantity A |
Quantity B |
The probability that both chips selected by Tarik will display a number less than 4. |
\(\frac{1}{2}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: Tarik has a pile of 6 green chips numbered 1 through 6 respe
[#permalink]
07 Aug 2018, 06:22
07 Aug 2018, 06:22
Expert Reply
Explanation
In this problem, Tarik is not picking 1 chip out of all 12. Rather, he is picking 1 chip out of 6 green ones, and then picking another chip out of 6 blue ones. There are 3 green chips with numbers less than 4, so Tarik has a \(\frac{3}{6}\) chance of selecting a green chip showing a number less than 4.
Likewise, Tarik has a \(\frac{3}{6}\) chance of selecting a blue chip showing a number less than 4.
Therefore, Quantity A is equal to \(\frac{3}{6}\times \frac{3}{6}=\frac{1}{2}\times\frac{1}{2}=\frac{1}{4}\). Quantity B is greater.
In this problem, Tarik is not picking 1 chip out of all 12. Rather, he is picking 1 chip out of 6 green ones, and then picking another chip out of 6 blue ones. There are 3 green chips with numbers less than 4, so Tarik has a \(\frac{3}{6}\) chance of selecting a green chip showing a number less than 4.
Likewise, Tarik has a \(\frac{3}{6}\) chance of selecting a blue chip showing a number less than 4.
Therefore, Quantity A is equal to \(\frac{3}{6}\times \frac{3}{6}=\frac{1}{2}\times\frac{1}{2}=\frac{1}{4}\). Quantity B is greater.
Re: Tarik has a pile of 6 green chips numbered 1 through 6 respe
[#permalink]
02 Jan 2019, 18:26
02 Jan 2019, 18:26
2
Answer: B
6 green chips, 1 to 6
6 blue chips, 1 to 6
Randomly 1 from greens and randomly one from blue
A: The probability that both chips will display a number less than 4: P(greens <4 and blues <4) = P(greens <4) * P(blues <4) = 3/6 * 3/6 = 1/4
B: 1/2
B is greater than A and the answer is B.
6 green chips, 1 to 6
6 blue chips, 1 to 6
Randomly 1 from greens and randomly one from blue
A: The probability that both chips will display a number less than 4: P(greens <4 and blues <4) = P(greens <4) * P(blues <4) = 3/6 * 3/6 = 1/4
B: 1/2
B is greater than A and the answer is B.
