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The angle ACD + the angle CDB
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25 Sep 2019, 15:43
25 Sep 2019, 15:43
Expert Reply
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Question Stats:
84% (00:32) correct
15% (00:43) wrong based on 13 sessions
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ABCD is a rectangle
Quantity A |
Quantity B |
\(m \angle ACD + m \angle CDB\) |
\(m \angle AEC + m \angle CED\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: The angle ACD + the angle CDB
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26 Sep 2019, 21:41
26 Sep 2019, 21:41
In a rectangle adjacent sides are at \(90\) degrees.
Therefore \(<ACD = 90\) degree similarly \(<CDB\) is also \(90\) degree.
Therefore qty A = \(90+90 = 180\)
Going to qty B
angles in a straight line add to 180 degree therefore qty \(B\) is also \(90\) degrees.
option C is the correct ans
Therefore \(<ACD = 90\) degree similarly \(<CDB\) is also \(90\) degree.
Therefore qty A = \(90+90 = 180\)
Going to qty B
angles in a straight line add to 180 degree therefore qty \(B\) is also \(90\) degrees.
option C is the correct ans
gmatclubot
Re: The angle ACD + the angle CDB [#permalink]
26 Sep 2019, 21:41
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