The base is not 10 units the height is 10 units.

The height of the triangle JKL and JKM are both the same 10 units.

Answer: D
as JMK is a right side triangle we have: 10^2 + (KL+LM)^2 = 26^2
So KL + LM = 24
Area of triangle JKL is 65. So height * KJ /2 = 65 -> height = 130/26 = 5 base is KJ and height is the one from angle L to the line KJ
On the other hand, MJL is also a right side triangle. We have 10^2 + ML^2 = jk^2
ML^2 = JK^2 - 10^2
with the given information we can't find out wanted values and the correct answer is D

Area of triangle JKL is 65. So height * KJ /2 = 65 .... This is incorrect.

Area of triangle JKL = height * KL /2 = 65

Answer is A right?

Base KL
Height 10

I agree.

An easier way to do this is to compare the areas and heights, since they are related as the two smaller triangles comprise of the largest triangle, and the height of all the triangles are equal to 10.

The largest triangle's, triangle JKM's, missing side MK can be solved for using 10^2 + (MK)^2 = 26^2, where MK is the base. Solving for MK results in 24. Now, calculate the area of triangle JKM using (1/2)bh, where b = 24 and h = 10. The area is 120.

It is stated that triangle JKL's area is 65. Per the drawing of the picture, we see that the area of triangle JKL + area of triangle JLM = area of triangle JKM, since the two smaller triangles make up the largest triangle, this means 65 + area of triangle JLM = 120. Area of triangle JKM thus is 55.

Now, we know the area of both smaller triangles (55 and 65), and since the 1/2 and h is the same for each of these smaller triangles, the only difference is the base that results in the difference in the size of the area. Therefore, the base for triangle JKL, which has the larger area of 65, must be larger. The base for triangle JKL is KL.

Choice A is the answer.

not sure why you're supporting pranab01's answer D. The correct answer is A..oddly confusing solution

Sandy is no longer part of the team, unfortunately I would say

The answer is A.

Ask if you do need further explanations

Regards

thanks for clarifying!

The area of \(JKL\) is 65 square meters

Quantity A	Quantity B
The length of side \(KL\)	The length of side \(LM\)

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

First, we have to find the length of side KM(KL+LM):

\(26^2 = KM^2 + 10^2\)

KM = 24

Now, we can find the area of the outer \(\triangle\)JKM:

\(\frac{1}{2}\)(10)(24)= 120

Then, subtract the area of the \(\triangle\)JKM from the given area of the \(\triangle\)JKL to the get the area of the \(\triangle\)JLM

120-65= 55

The area of \(\triangle\)JLM= \(\frac{1}{2}\)(10)(LM) = 55

LM = 11

Now, we can find the length of KL:

KL= KM-LM = 24-11

KL = 13

Since KL > LM, the correct answer is A

Please follow the rules posting on the board

https://gre.myprepclub.com/forum/rules-for ... -1083.html

And how to format a question the easy way https://gre.myprepclub.com/forum/how-to-po ... 12752.html

As I did above. Thank you

Regards

Its easy to solve once you identify that JM is length and not width. The question is, how to assume or consider JM as length and not width?

May I please know why this is incorrect?
Area of triangle is 1/2 * base * height where height is measured from the opposite vertex to the opposite base. Here it should be 1/2 * KJ * JM right?

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